原题链接 http://projecteuler.net/problem=38

Pandigital multiples

Take the number 192 and multiply it by each of 1, 2, and 3:

192 * 1 = 192

192 * 2 = 384

192 * 3 = 576

By concatenating each product we get the 1 to 9 pandigital, 192384576. We will call 192384576 the concatenated product of 192 and (1,2,3)

The same can be achieved by starting with 9 and multiplying by 1, 2, 3, 4, and 5, giving the pandigital, 918273645, which is the concatenated product of 9 and (1,2,3,4,5).

What is the largest 1 to 9 pandigital 9-digit number that can be formed as the concatenated product of an integer with (1,2, … , n) where n >1?

全位数乘数

取数字192，将它乘以分别乘以1,2和3：

192 * 1 = 192

192 * 2 = 384

192 * 3 = 576

将这些乘积连接起来，我们将得到一个从1到9的全位数，192384576.我们称192384576为192和(1,2,3)的乘积连接

类似的，我们可以从9开始，将它乘以1,2,3,4和5，得到一个全位数，918273645，即为9和(1,2,3,4,5)的乘积连接。

求由一个整数和(1,2,…,n, n > 1)的乘积连接中得到的1到9的全位数中，最大的那个。

解法：

这题没什么好说的。